Question

A penny is dropped from the Statue of Liberty

a. what is the velocity of the penny after 0.30 seconds

b. How far did the penny drop after 0.30 seconds

Answer 1

a) The velocity is 2.94m/s

b) 0.441

Step-by-step explanation:

a) Assume gravity is 9.8m/s^2

Use the equation below to solve for the velocity at 0.30 seconds

`vf=vi+at`,

vf =unknown velocity vi= initial velocity vi=0m/s a= 9.8m/s^2 t=0.30seconds

Step 1: Substitute the variables with the knowns

`vf=0m/s+(9.8m/s^2)*0.30seconds`

Step 2: Solve

`vf=2.94m/s`

b)

Use the equation below to solve for the displacement at 0.30 seconds

`x=vit+(1)/(2) at^(2)`

Step 1: Substitute the same variables with the knowns

`x=(1)/(2)*(9.8m/s^2)*(0.30seconds)^(2)`

Note that vi*t=0 as vi=0m/s

Step 2: Solve

x=0.441m