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1 vote
Equation of a line that passes through (2,1) and (-2,7)

asked
User Mikdiet
by
9.0k points

1 Answer

3 votes

Answer:

y = (3/-2)x + 4

Explanation:

the equation you want to find is in the form of y = mx + b

(y2 - y1) / (x2 - x1) is a formula to determine the slope of a line from two points

(7 - 1) / ([-2] - 2) = m (m meaning slope)

6 / -4 = m

3 / -2 = m

now that you know m, you can solve for b by inserting one of the points in the slope form equation and the slope

y = mx + b

1 = (3/-2)(2) + b

1 = -3 + b

add three to both sides

4 = b

the equation will be y = (3/-2)x + 4

answered
User Maddhruv
by
8.0k points

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