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How many moles of Oz would be required to generate 13.0 mol of NO2 in the reaction below assuming the reaction has only 74.1% yield? 2 NO (g) + O2 (g) → 2 NO2 (g)

How many moles of Oz would be required to generate 13.0 mol of NO2 in the reaction below assuming the reaction has only 74.1% yield? 2 NO (g) + O2 (g) → 2 NO2 (g)
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How many moles of Oz would be required to generate 13.0 mol of NO2

in the reaction below assuming the reaction has only 74.1% yield?
2 NO (g) + O2 (g) → 2 NO2 (g)

asked
User Jon Weers
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7.7k points

1 Answer

3 votes

Answer:32

Step-by-step explanation:

Have a nice day :)

answered
User Aphax
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