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Write a quadratic equation with roots of 1/ 3 and − 7/ 2 .

A) y = (x − 3)(7x + 2)
B) y = (x + 3)(7x − 2)
C) y = (3x − 1)(2x + 7)
D) y = (3x + 1)(2x − 7)

asked
User FloF
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1 Answer

5 votes

Answer:


x = (1)/(3) or \: x = - (7)/(2) \\ 3x - 1= 0 \: or \:2 x + 7 = 0 \\ \therefore(3x - 1)(2 x + 7)

answered
User Vadiraja K
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