Question

How high is a cliff if it takes 10 seconds for an object to hit the Earth's surface (assume the object is released from the top of the cliff).

Answer 1

Step-by-step explanation:

laws of motion

H=ut + 0.5gt^2

but u(initial velocity)=0 and g=10m/s^2

H=5t^2

=5×10^2

=5 × 100

=500m