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Solve for k,x,y and, yz

Solve for k,x,y and, yz-example-1
asked
User Odalet
by
8.4k points

1 Answer

4 votes

Answer:

k = 3

XY = 33

YZ = 48

Explanation:

X___Y___Z

XZ= XY + YZ

81 = (12k-3) + (3+15k)

81 = 27k

27k = 81

k= 81/27

k = 3

XY= 12k-3 = 12(3) - 3 = 36 - 3 = 33

YZ = 3+15k = 3 + 15(3) = 3 + 45 = 48

I hope I helped you^_^

answered
User Willem Renzema
by
8.3k points

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