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Given that (x-3)(Ax²+bx+c)=x³-7x-6,find the value of A,B and C​

Given that (x-3)(Ax²+bx+c)=x³-7x-6,find the value of A,B and C​
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Given that (x-3)(Ax²+bx+c)=x³-7x-6,find the value of A,B and C​

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User Nimph
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Answer:

Given that (x-3) (Ax²+bx+c) = x³-7x-6, find the value of A, B and C

Given that (x-3) (Ax²+bx+c) = x³-7x-6, find the value of A, B and C

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User Bsegraves
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x³+ax²+bx+6 has (x-2) as factor and leaves remainder 3 when divided by (x-3), find values of a and b​
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