Question

2 raised to power (4_6x) =8(1-x)​

Answer 1

Explanation:

`2^(4-6x)=8^(1-x)\\\\2^(4-6x)=(2^(3))^(1-x)\\\\2^(4-6x)=2^(3*(1-x)}\\\\2^(4-6x)=2^(3-3x)`

Bases are equal, so compare the powers,

4 - 6x = 3 - 3x

Subtract 3 from both sides,

4 - 3 - 6x = -3x

1 - 6x = -3x

Add 6x to both sides

1 = -3x+ 6x

1 = 3x

Divide both sides by 3

1/3 = x

x = 1/3