Question

A student needs to make 0.855 L of a sodium bromide solution for an experiment. The concentration of the required solution is 0.350 M. How many grams of sodium bromide will he need to use?

Answer 1

Step-by-step explanation:

Molarity = moles/liters of solution

moles = molarity x Liters of solution

= 0.350 m/L x 0.855 L

= 0.299 mol

mass = moles x molar mass

= 0.299 mol x 102.89 g/ms

= 30.78 grams