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$D$ is on side $\overline {AB}$ of $\triangle ABC.$ We know $\triangle ABC \sim \triangle ACD$ and $\angle A =48^\circ.$ If $BC=BD,$ what is $\angle B$ in degrees?

$D$ is on side $\overline {AB}$ of $\triangle ABC.$ We know $\triangle ABC \sim \triangle ACD$ and $\angle A =48^\circ.$ If $BC=BD,$ what is $\angle B$ in degrees?
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$D$ is on side $\overline {AB}$ of $\triangle ABC.$ We know $\triangle ABC \sim \triangle ACD$ and $\angle A =48^\circ.$ If $BC=BD,$ what is $\angle B$ in degrees?

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User Hozefam
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28

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User Jimmy Sanchez
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