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A box contains 10 light bulbs, of which 3 are defective and the other 7 work. If two bulbs are drawn in succession without replacement, what is the probability of getting 1 work…

A box contains 10 light bulbs, of which 3 are defective and the other 7 work. If two bulbs are drawn in succession without replacement, what is the probability of getting 1 work…
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A box contains 10 light bulbs, of which 3 are defective and the other 7 work. If two bulbs are drawn in succession without replacement, what is the probability of getting 1 working bulb and 1 defective bulb?

asked
User Jim Driscoll
by
8.9k points

1 Answer

6 votes

Answer:

Working: 7/10

defective:3/10

Explanation:

Just trust me

answered
User Chatpitau
by
8.0k points
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