Question

The sum of three numbers is 66. The second number is twice the first and six less than the third. find the numbers

Answer 1

Explanation:

let the 1st number be x

and,

2nd number = 2x

3rd number = 2x + 6

their sum = 66

so, after inserting the values we got

→ x + 2x + 2x + 6 = 66

→ 5x + 6 = 66

→ 5x = 66 - 6 = 60

→ x = 60/5 = 12

→ x = 12

therefore,

1st number = x = 12

2nd number = 2x = 12 × 2 = 24

3rd number = 2x + 6 = 24 + 6 = 30

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