Question

If an object starts with a velocity of 5.26 m/s

and ends with a velocity of 60.7 m/s in 15.0

seconds, what is its displacement?

Answer 1

Displacement = 8.4m

Step-by-step explanation:

Hope that this is helpful.

Have a great day.

`v = 60.7m {s}^( - 1) \: u \: = 5.26m {s}^( - 1 ) \: t = 15s \: \: \: \: \: \\ a \: = (v - u)/(t) \\ a \: = (60 .7- 5.26)/(15) \\ a = 3.7m {s}^( - 28) \\ {v}^(2) = {u}^(2) + 2as \\ {60.7}^(2) = {5.26}^(2) + 2 * 3.7 * s \\ 60.7 =27 .7 + 2 * 3.7s \\60.7 = 29.7 * 3.7s \\ 60.7 - 29.7 = 3.7s \\ 31 = 3.7s \\ (31)/(3.7) = (3.7s)/(3.7) \\ s = 8.4m`