Question

A particle is projected from the ground with an initial speed of 'v' at an angle of 0 with horizontal. The average velocity of the particle between it's point of projection and height point of trajectory is?

A. v/2 √1+2cos^2 0 C. v/2√1+3cos^2 0
B. v/2√1+cos^2 0 D. vcos0

Answer 1

If the particle was projected at an angle of zero with the horizontal, that is the highest point of the trajectory, and (D) is correct.