Question

An exterior of a triangle is 110° and one of the interior opposite angle is 30°.Find the other two angles of the triangle.​

Answer 1

Explanation:

In ∆ ABC,

∠ACD = ∠ABC + ∠BAC

110° = 30° + ∠BAC

∠BAC = 110° - 30°

∴∠BAC = 80°

∴ 3rd ∠ACB = 180° - (30° + 80°)

= 180° - 110°

= 70°

Answer:

Hence, the other two angles of the triangle are 80° and 70°.

Hope this helps!!

Answer 2

80° and 70°

Explanation:

As we know,

sum of interior angles equal to exterior angle which is opposite to them

so , 30° + x° = 110°

therefore, x° = 80°

also, by angle sum property of a triangle which states sum of all interior angles of a triangle = 180°

other inter angle will be 70° .