Question

the time period of an oscillating body is T how will the time of the period vibrating body change if the value of G is decreased by 9 times

Answer 1

`\\ \sf\longmapsto T_1=2\pi \sqrt{(m)/(g)}`

• g be x

`\\ \sf\longmapsto T_1=2\pi \sqrt{(m)/(x)}`

• G be 9x

`\\ \sf\longmapsto T_2=2\pi \sqrt{(m)/(G)}`

`\\ \sf\longmapsto T_2=2\pi \sqrt{(m)/(9x)}`

Now

`\\ \sf\longmapsto (T_1)/(T_2)=\frac{2\pi \sqrt{(m)/(x)}}{2\pi \sqrt{(m)/(9x)}}`

`\\ \sf\longmapsto (T_1)/(T_2)=(1)/(9)`

`\\ \sf\longmapsto T_1:T_2=1:9`

The time period will increase by 9 times