Question

How to solve 9(a + 2b) + c for a = -3, b = -2, and c = 1.

Answer 1

Answer: Solve for P: WR - 1 =R (1 – P) 10. ... Solve for B: A= 2B + C 12. ... 9. Solve for P: WR - 1 =R (1 – P).

Explanation:

Answer 2

Substitute the values of a, b, and c into the given equation:

9(a + 2b) + c

= 9[(-3) + (-2)] + 1

You must work on the inside terms first by adding -3 and -2 before multiplying by 9.

= 9(-5) + 1

= -45 + 1
= -44