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(x + 2)(3x – 1) = 0 X^2+4x=0 2m^2-128=0 2x^2+3x-14=0

(x + 2)(3x – 1) = 0 X^2+4x=0 2m^2-128=0 2x^2+3x-14=0
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(x + 2)(3x – 1) = 0

X^2+4x=0

2m^2-128=0

2x^2+3x-14=0

asked
User Alaa Kanaan
by
8.0k points

1 Answer

6 votes

Explanation:

x^2+4x=0

therefore x=-4

answered
User Dtyler
by
8.0k points
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