Question

6. Neon has 10 electrons - 2 in the inner shell and 8 in the outer shell. This arrangement of 8 electrons in the

outer shell is extremely stable and makes neon inert, with a valence of zero. Sodium has 11 electrons - 2
in the first shell, 8 in the next shell, and I in the outer shell. Fluorine has 9 electrons - 2 in the first shell
and 7 in the outer shell. How could sodium and fluorine from a compound in which both elements would
be like neon with 8 electrons in the outer shell?

Answer 1

Let look at EC of Sodium(Na)

`\\ \sf\longmapsto 1s^22s^22p^63s^1`

• valency= +1

Now look at EC of Fluorine

`\\ \sf\longmapsto 1s^22s^22p^5`

• Valency=-1

Now the Compound will be

`\\ \sf\longmapsto NaF`