Question

The ages of three friends are consecutively one year apart. Together, their ages total 66 years. Which equation can be used to find the age of each friend (where represents the age of the youngest friend)?

x=____.

Answer 1

21, 22, and 23 years old.

Explanation:

1) x

2) x+1

3) x+2

x + x +1 + x + 2 = 66

3x +3 = 66

3x = 66-3

x = 63/3

x = 21

Answer 2

First friend = 21 years

Second friend = 22 years

Third friend =23 years

Explanation:

Age of first friend = x

Age of second friend = x+ 1

Age of third friend = x+ 2

Sum of ages = 66

(x) + (x+1) +(x + 2) = 66

3x + 3 = 66

3x = 66-3

3x = 63

x =
`(63)/(3)`

x= 21

First friend = x = 21 years

Second friend = x+1 = 21 +1 =22 years

Third friend = x+2 =21 +2 =23 years

Hope this helps.