Question

What is the statement?

Answer 1

Proof:

In △ABC and △DCB,

CB = CB (common)

∠ABC = ∠BCD (each 90°)

and AB = CD (given)

(i) ∴ △ ABC ≅ △DCB (S.A.S. Axiom)

(ii) Hence AC = DB (c.p.c.t.)

Hence proved.