Answer:
Explanation:
XB bisects ∠AXC.
⇒ ∠AXB = ∠BXC = 6x + 40
∠AXB + ∠BXC = ∠AXC
6x + 40 + 6x + 40 = 7x + 100
6x + 6x + 40 + 40 = 7x + 100
Add like terms
12x + 80 = 7x +100
Subtract 80 from both sides
12x = 7x + 100 -80
12x = 7x + 20
Subtract 7x form both sides
12x - 7x = 20
5x = 20
Divide both sides by 5
x = 20/5
x = 4
∠AXC = 7x + 100
= 7*4 + 100
= 28 + 100
∠AXC = 128