Question

2x-3x²=5 in standard formation​

Answer 1

Bc 2x—x3=ew.r divorce

Answer 2

Explanation:

1. Make the equation equal to zero

2x - 3x^2 = 5 = 0

2. Then apply simple algebra by subtracting -5 from +5

2x - 3x^2 = 5 = 0

-5

3. Now move the -5 to the left side of the equation

2x - 3x^2 -5 = 0

4. Now arrange the numbers into standard form (ax^2 + bx + c)

-3x^2 + 2x - 5