Question

In the given kite, SZ= 10 yards, WZ= 10 yards, TZ= 12 yards, and RZ= 32 yards. Determine the area of the kite.

Answer 1

440yd

Explanation:

If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:

... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)

... A = 440 yd²