Question

A car is brought to rest uniformly in 6 seconds. The initial velocity of the car was 24 m/s. How far does the car travel while decelerating?

Answer 1

v=u+at

24=0+at

24=a×6

a=4m/s

hence

s=ut+at^2÷2

s=36m

Step-by-step explanation:

since the car is brought to rest the u=0