asked 203k views
5 votes
/10

How many individual decay steps are in the decay chain of
uranium-238 before the stable end product of lead-206 is
produced?

1 Answer

5 votes

Step-by-step explanation:

Uranium-238 undergoes a radioactive decay series consisting of 14 separate steps before producing stable lead-206. This series consists of eight α decays and six β decays.

answered
User Steve Konves
by
8.3k points
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