Question

An object of volume 4 x 10^-4 m³ and density 6000kg/m³ is immersed inside a fluid of density 5000kg/m³. The force exerted by the fluid on the object is 0.7N. Calculate the density of the fluid

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Answer 1

P = m/v
6000 kg/m3 = m/4x10^-4
m = 2.4 kg

P = m/v
5000 kg/m3 = 2.4kg/v
V = 4.8 x 10^-4

0.7N x 10 = 7kg

P = m/v
P = 7/4.8 x 10^-4
P answer = 1458.3

It is right?