The perimeter of a rectangle is 60 feet. Find its dimensions assuming that its length is 9 feet less than twice its width

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asked Jul 15, 2022 191k views

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Gowire · Answer 1 · 2022-07-20T04:02:33+0000

Let width = x
Length = 2x - 9
Perimeter = 2w + 2l
2(x) + 2(2x - 9) = 60 feet
2x + 4x - 18 = 60 feet
6x = 78 feet, x = 13
Therefore width = 13 feet
Length = 2(13) - 9 = 17 feet

The perimeter of a rectangle is 60 feet. Find its dimensions assuming that its length is 9 feet less than twice its width

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