Question

PLEASE HURRY 50 POINTS!!

What is the solution set for 3(1−r)<−2r−4?

r>7

r<1

r>−7

r<−1

Answer 1

the solution set is r>7

step by step:

Subtract 3 from both sides

3−3r−3<−2r−4−3

Simplify

−3r<−2r−7

Add 2r to both sides

−3r+2r<−2r−7+2r

Simplify

−r<−7

Multiply both sides by −1 (reverse the inequality)

(−r)(−1)>(−7)(−1)

Simplify

r>7