Question

How do you do this geometry question?

Answer 1

Answer: B: 150°

Explanation:

`|EF|=\sqrt{1^2-((1)/(2))^2}}=\sqrt{(3)/(4) } =(√(3) )/(2) \\\\tan(\alpha)=(1-(√(3) )/(2) )/((1)/(2) ) =2-√(3) \Longrightarrow\ \alpha=15^o \\\\mes\widehat{BEC}=180^o-2*15^o=150^o\\\\Answer\ B`