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Sin30. cot45/cos30. tan60​

Sin30. cot45/cos30. tan60​
asked 80.8k views
3 votes
Sin30. cot45/cos30. tan60​

asked
User Afsar
by
7.4k points

1 Answer

3 votes

Answer:


( \sin(30) \cot(45) )/( \cos(30) \tan(60) ) \\

group them by simplifying:


= \{ ( \sin(30) )/( \cos(30) ) . ( \cot(45) )/( \tan(60) ) \} \\ \\ = ( \tan(30) )/( \tan(45) \tan(60) ) \\ \\ = (( (1)/( √(3) )) )/(1 * √(3) ) \\ \\ = (1)/( √(3) ) * (1)/( √(3) ) \\ \\ = \frac{1}{ {( √(3)) }^(2) } \\ \\ = { \boxed{ \boxed{ (1)/(3) }}}

answered
User Punitcse
by
8.3k points
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