Question

If a trapezoid has an area of 60 m² and bases of 2 m and 6 m, what's its height?

Answer 1

Given :

• Base = 2 m and 6 m.

• Area = 60 m².

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To find :

• The height.

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Solution :

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We know,

`{ \longrightarrow{\qquad \sf{ \pmb {(1)/(2 ) * (b_(1) + b_(2)) * h = {Area_((Trapezoid)) } }}}}`

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Now, Substituting the values :

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`{ \longrightarrow{\qquad \sf{ {(1)/(2 ) * (2 + 6) * h = {60 } }}}}`

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`{ \longrightarrow{\qquad \sf{ {(1)/(2 ) * 8 * h = {60 } }}}}`

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`{ \longrightarrow{\qquad \sf{ {(8)/(2 ) * h = {60 } }}}}`

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`{ \longrightarrow{\qquad \sf{ 4 * h = {60 } }}}`

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`{ \longrightarrow{\qquad \sf{ h = { (60)/(4) } }}}`

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`{ \longrightarrow{\qquad \sf{ \pmb { h = {15} } }}}`

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Therefore,

• The height of the trapezoid is 15 m .