Answer:
Corrected Question: 
 [ Refer to the above attachment ] 
Solution: 
In the given figure there are two shapes:
- A Rectangle
- A Triangle 
First, we have to find the area of Rectangle ABGF & DCGE. After that, area of triangle CHB. 
1) Area of Rectangle ABGF: 
As, we know: 
Formula for Area :-
 ★ Length × Breadth ★ 
where, 
- Length = FA = 4cm 
- Breadth = GF = 10cm ( 7+3 ) 
➝ 4 cm × 10 cm
➝ 40 cm² 
Hence, the area of Rectangle ABGF is 40cm². 
2) Area of Rectangle DCGE: 
As, we know: 
Formula for Area :- 
 ★ Length × Breadth ★ 
where, 
- Length = ED = 4cm 
- Breadth = DC = 7cm 
➝ 4 cm × 7 cm 
➝ 28 cm² 
Hence, the area of Rectangle DCGE is 28cm². 
3) Area of Triangle CHB: 
As, we know: 
Formula for Area :- 
 ★ ½ ( base × height ) ★ 
where, 
➝ ½ ( 3cm × 8cm ) 
➝ ½ ( 24cm ) 
➝ ½ × 24cm 
➝ 12 cm² 
Hence the Area of Triangle CHB is 12cm². 
Now, Area of Given Shape is: 
➝ 40cm² + 28cm² + 12cm² 
➝ 52cm² + 28cm² 
➝ 80cm² 
Thus, the area of the given shape is 80cm². 
____________________
Additional Information: 
 [ Formula's for Area ] 
★ Square = (Side)² 
★ Rectangle = Length × Breadth 
★ Triangle = ½bh 
★ Circle = πr²