Question

Hi help me plsss :(((

Answer 1

The square root of 121 is 11, the square root of x^2 is x, the square root of y^3 is y and sqrt y, the square root of z^4, is z^2:

11xyz^2 sqrt(y)

Your answer is C

Note: If something is inside a radical, it is raised to an exponent of 1/2. You can rewrite anything inside the radical as raised to 1/2.

Answer 2

The choice 3.

`11xy {z}^(2) √(y)`

Explanation:

`\sqrt{121 {x}^(2) {y}^(3) {z}^(4) } = \sqrt{ {11}^(2) {x}^(2) {y}^(2)y ({z}^(2)) ^(2) } \\ \\ = 11xy {z}^(2) √(y)`