asked 233k views
2 votes
Factor by grouping.
12x³+ 4x²+ 3x + 1​

1 Answer

4 votes

Answer:


→12 {x}^(3) + 4 {x}^(2) + 3x + 1 \\ = 4 {x}^(2) (3x + 1) + 1(3x + 1) \\ = \boxed{(3x + 1)(4 {x}^(2) + 1)}✓

  • (3x+1)(4x²+1) is the right answer.
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