Question

Write the equation of the line that passes through
(6,-5) and is perpendicular to y = 2x+3.

Answer 1

Explanation:

y = 2x + 3

Slope = 2

The slope of the perpendicular line = -1/m = -1/2

m = -1/2 ; (6, -5)

y = mx +b

Here, plugin x = 6 ; y = -5 and m = -1/2

`-5 = (-1)/(2)*6+b\\\\-5=-3+b\\\\\\-5 + 3 = b\\\\b = -2`

Equation of the line: y = mx +b

`y =(-1)/(2)x -2`