Question

Please help I only have until 8:15 AZ time ;-;

Twice a​ number, increased by one​, is between negative 3 and 9. Find all the numbers.

Answer 1

`\large \mathfrak{Solution : }`

let the number be " x "

The Inequality can be represented as :

• 
  `- 3 < 2x + 1 < 9`

• 
  `- 3 - 1 < 2x + 1 - 1 < 9 - 1`

• 
  `- 4 < 2x < 8`

• 
  `( - 4)/(2) < (2x)/(2) < (8)/(2)`

• 
  `- 2 < x < 4`

therefore the number actually lies between - 2 and 4, so the possible values for the number (if it's an integer) is -1 , 0 , 1 , 2 , and 3 .

Answer 2

Explanation:

-3 < 2x+1 <9

-3-1 < 2x < 9-1

-4 < 2x < 8

-2 < x < 4

so, the numbers are between -2 and 4

for Integers : -1, 0, 1, 2, 3