Question

PLS HELP QUICK ALOTTT OF POINTS

How many moles are in 4.8x10^23 F atoms?

Answer in units of mol.

the atomic mass of fluorine is:19.00

Answer 1

`\boxed {\boxed {\sf 0.80 \ mol\ F}}`

Step-by-step explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

`\frac {6.022 * 10^(23) \ atoms \ F}{ 1 \ mol \ F}`

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

`4.8 * 10^(23) \ atoms \ F *\frac {6.022 * 10^(23) \ atoms \ F}{ 1 \ mol \ F}`

Flip the ratio so the units of atoms of fluorine cancel each other out.

`4.8 * 10^(23) \ atoms \ F *\frac { 1 \ mol \ F}{6.022 * 10^(23) \ atoms \ F}`

`4.8 * 10^(23) *\frac { 1 \ mol \ F}{6.022 * 10^(23) }`

Condense into 1 fraction.

`\frac { 4.8 * 10^(23) }{6.022 * 10^(23) } \ mol \ F`

Divide.

`0.7970773829 \ mol \ F`

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

`0.80 \ mol \ F`

4.8 × 10²³ fluorine atoms are equal to 0.80 moles of fluorine.