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3x/2x-6+9/6-2x=3x/2x-6+9/a(2x-6)=3x/2x-6+b/2x-6=3x-c/2x-6=d(x-e)/f(x-3)=g

3x/2x-6+9/6-2x=3x/2x-6+9/a(2x-6)=3x/2x-6+b/2x-6=3x-c/2x-6=d(x-e)/f(x-3)=g
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3x/2x-6+9/6-2x=3x/2x-6+9/a(2x-6)=3x/2x-6+b/2x-6=3x-c/2x-6=d(x-e)/f(x-3)=g

asked
User Meily
by
8.1k points

1 Answer

7 votes

Answer:A= -1

B=-9

C=9

D=3

E=3

F=2

G=1.5

On edge

Explanation:

answered
User Uday Sawant
by
8.5k points
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