Question

Solve tan(3x)+1=0
Pls show work

Answer 1

tan(3x)+1=0

=> tan (3x)=-1

=> 3x = −π/4+k.π,k∈Z

=> x= −π/12+k.π/3,k∈Z

Explanation:

Answer 2

Explanation:

tan(3x)+1=0

⇔tan3x=-1

⇔tan3x=tan(
`(-\pi )/(4)`)

⇔3x=
`(-\pi )/(4)`+k
`\pi`

⇔x=
`(-\pi )/(12)`+
`(k\pi )/(3)`