Question

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.​

Answer 1

`\textsf{area of a sector}=(\theta\pi r^2)/(360\textdegree) \mathsf{\ \ (where\ \theta \ is\ in\ degrees)}`

Given:

• radius (r) = 6 cm
• 
  `\theta` = 60°

`\implies \textsf{area}=(60\textdegree *\pi * 6^2)/(360\textdegree)`

`\implies \textsf{area}=(2160\pi)/(360)`

`\implies \textsf{area}=6\pi \textsf{ cm}^2`

`\implies \textsf{area}=18.85\textsf{ cm}^2 \textsf{ (nearest hundredth)}`