Answer: 2 • (y2 + 11y + 14)
Explanation:
Changes made to your input should not affect the solution:
(1): "y2" was replaced by "y^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(((8•(y2))+7y)+4)-(3•((2y2-5y)-8))
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 2y2-5y-8
The first term is, 2y2 its coefficient is 2 .
The middle term is, -5y its coefficient is -5 .
The last term, "the constant", is -8
Step-1 : Multiply the coefficient of the first term by the constant 2 • -8 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is -5 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6
-1 + 16 = 15
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step
2
:
(((8•(y2))+7y)+4)-3•(2y2-5y-8)
STEP
3
:
Equation at the end of step
3
:
((23y2 + 7y) + 4) - 3 • (2y2 - 5y - 8)
STEP
4
:
STEP
5
:
Pulling out like terms
5.1 Pull out like factors :
2y2 + 22y + 28 = 2 • (y2 + 11y + 14)
Trying to factor by splitting the middle term
5.2 Factoring y2 + 11y + 14
The first term is, y2 its coefficient is 1 .
The middle term is, +11y its coefficient is 11 .
The last term, "the constant", is +14
Step-1 : Multiply the coefficient of the first term by the constant 1 • 14 = 14
Step-2 : Find two factors of 14 whose sum equals the coefficient of the middle term, which is 11 .
-14 + -1 = -15
-7 + -2 = -9
-2 + -7 = -9
-1 + -14 = -15
1 + 14 = 15
2 + 7 = 9
7 + 2 = 9
14 + 1 = 15
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored