Question

Help (Geomotry)question3.

Answer 1

8x+11=14x_1

14x_8x=11+1

6x=12

x=12/6

x=2

Answer 2

`\huge \boxed{\mathfrak{Question} \downarrow}`

• Find the measure of JL.

`\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}`

Given, K is the midpoint of JL. So, JK = KL.

• KL = 14x - 1
• JK = 8x + 11
• JL = ?

________

JL = JK + KL (given that K is the midpoint of JL)

JL = (8x + 11) + (14x - 1)

________

`\large \boxed{\mathfrak{Steps} \downarrow}`

`\sf( 8 x + 11 ) + ( 14 x - 1 )`

Combine 8x and 14x to get 22x.

`\sf \: 22x+11-1`

Subtract 1 from 11 to get 10.

`\boxed{ \boxed{ \bf22x+10 }}`

________

Also given that, JK = KL.

So, (8x + 11) = (14x - 1)

⇨ (8x + 11) = (14x - 1)

⇨ 8x + 11 = 14x - 1

⇨ 11 + 1 = 14x - 8x

⇨ 12 = 6x

⇨ x = 12 / 6

⇨
`\boxed{ \boxed{ \bf \: x= 2 }}`

________

Now, value of JL will be,

JL = 22x + 10

Substitute the value of x.

JL = 22(2) + 10

JL = 44 + 10

`\boxed{ \boxed{ \bf\: JL = 50 }}`

⇨ So, the value of JL will be 50 units.