Question

3tanx3x=3 square rooted
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Answer 1

`\tan 3x=(√(3) )/(3) =(1)/(√(3) ) =tan(\pi )/(6) =tan (n\pi +(\pi )/(6) )\\3x=n\pi +(\pi )/(6) =((6n+1)\pi )/(6) \\x=((6n+1)\pi )/(18) \\where~x~is~an~integer.`

Explanation:

tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\

where~x~is~an~integer.