Question

The temperature in Celsius would be,

Answer 1

First derisive the equation for C

`\\ \sf\longmapsto F=(9)/(5)C+32`

`\\ \sf\longmapsto C+32=(5)/(9)F`

`\\ \sf\longmapsto C=(5)/(9)F-32`

• F=101F

`\\ \sf\longmapsto C=(5)/(9)101-32`

`\\ \sf\longmapsto C=(505)/(9)-32`

`\\ \sf\longmapsto C=56.1-32`

`\\ \sf\longmapsto C=24.1°C`