Question

The volume (V) of an enclosed mass of gas is 350kPa. The pressure of the endlosed gas is now decreased to 125kPa, at constant temperature. What will the new volume of the gas be, in terms of V (2)​

Answer 1

Answer: V1/V2 = 0.357,

V2 = (V1/0.357) or 28.0*V2

Explanation: Use the combined gas law: P1V1/T1 = P2V2/T2 We want to find V1/2 (or V2/V1). Rearrange:

V1/V2 = (P2/P1)(T1/T2)

The units all cancel. Temerature is constant, so (T1/T2) = 1.

V1/V2 = (125/350)*(1)

V1/V2 = 0.357