Question

Help me I need this like really !!

Answer 1

`radius=2√(6)`

Explanation:

`AB^2\:+\:BC^2\:=AC^2`

`AB^2\:+\:5^2\:=7^2`

`AB^2\:+\:25\:=49`

`AB^2\:=24`

`AB=√(24)=√(4*6)=2√(6)`

Answer 2

r = 2
`√(6)`

Explanation:

the radius r of the circle is AB

the angle between a tangent and the radius at the point of contact = 90°

then Δ Abc is a right triangle

using Pythagoras' identity

AB² + BC² = AC² ( substitute values )

AB² + 5² = 7²

AB² + 25 = 49 ( subtract 25 from both sides )

AB² = 24 ( take square root of both sides )

AB =
`√(24)` =
`√(4(6))` =
`√(4)` ×
`√(6)` = 2
`√(6)`