Determine the value of k for which the graph of y=kx^3 pass through the point (-2,1)

Question

asked Jul 25, 2022 5.6k views

1 Answer

Adesina · Answer 1 · 2022-07-29T03:30:53+0000

Answer:

$\displaystyle k = -(1)/(8)$

Explanation:

We are given the equation:

$\displaystyle y = kx^3$

And we want to determine the value of k such that the graph passes through the point (-2, 1).

Hence, when x = -2, y = 1. Substitute:

$\displaystyle (1) = k(-2)^3$

Simplify:

$\displaystyle 1 = -8k$

Hence:

$\displaystyle k = -(1)/(8)$