asked 160k views
4 votes
The upward normal force exerted by the floor is 620 n on an elevator passenger who weighs 650 n

asked
User Zevero
by
7.2k points

1 Answer

2 votes

Answer:


\alpha = 0.45 (m)/(s^(2) ) downward

Step-by-step explanation:

Hope this helps

answered
User Dribbel
by
8.3k points
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