Question

Write the equation of the line that
passes through (5,-7) and (0, -1)

Answer 1

4,3,2,1,0,-1, -2, -3, -4,

Answer 2

Equation of a line can be given by :

y = mx + b

Let's find the slope of the line (m) :

`\mathcal{ \hookrightarrow \: (y_2 - y_1)/(x_2 - x_1) }`

`\mathcal{ \hookrightarrow \: ( - 1 - ( - 7))/(0 - 5) }`

`\hookrightarrow \: (6)/( - 5)`

`\hookrightarrow \: m = ( - 6)/(5)`

now let's solve for b :

`\hookrightarrow \: y = mx + b`

Let's plug the values of x and y from the coordinates of a point .

`\hookrightarrow \: - 7 = (( - 6)/(5) * 5) + b`

`\hookrightarrow \: - 7 = - 6 + b`

`\hookrightarrow \: b = - 1`

now, let's put the value of m (slope) and b (y-intercept) in the equation.

`\hookrightarrow \: y = mx + b`

`\boxed{ \boxed{\: y = ( - 6)/(5)x - 1 }}`

That's All, I hope it helped ya